( N = 35 ), ( N/2 = 17.5 ) → Median class = 20-30 ( L = 20, cf = 13, f = 12, h = 10 ) Median = ( 20 + \frac17.5 - 1312 \times 10 = 20 + 3.75 = 23.75 ) Example 3: Mode – Continuous Series | Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | |-------|------|-------|-------|-------|-------| | f | 4 | 9 | 15 | 8 | 2 |
Can a distribution have two modes? Ans. Yes → bimodal distribution. ( N = 35 ), ( N/2 = 17
Write the empirical formula for mode. Ans. Mode = 3 Median – 2 Mean Write the empirical formula for mode
Modal class = 20-30 (( f_1 = 15 )) ( L = 20, f_0 = 9, f_2 = 8, h = 10 ) Mode = ( 20 + \frac15 - 92\times15 - 9 - 8 \times 10 = 20 + \frac613 \times 10 ) = ( 20 + 4.615 = 24.615 ) 4. Important Short Answer Questions (as per Sandeep Garg) Q1. When is median preferred over mean? Ans. – Open-ended classes, skewed distribution, ordinal data, presence of extreme values. Important Short Answer Questions (as per Sandeep Garg) Q1
What is the median class? Ans. The class where cumulative frequency first exceeds ( N/2 ).
